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Create an data type with identity(1, 1) property

Hello!

Code Snippet

--I'm trying this command:
create type int8 from tinyint identity(1,1) not null

But, an error occurs: don't possible create an data type with identity property....... Correct?

How to create an data type with identity property? The 'sys.sp_addextendedproperty' SP is the solution? An example, please?

Bye!

[474 byte] By [DenisBittencourtMuniz] at [2008-1-5]

«« SEPA Testing
»» Value type and interface

# 1

The IDENTITY property is linked to a table -as well as a datatype.

CREATE TABLE MyTable

( RowID int IDENTITY,

MyDate varchar(20)

)

You cannot simply CREATE TYPE or DECLARE a variable and also have an IDENTITY property for the type/variable.

ArnieRowland at 2007-10-3 >

top of Msdn Tech,SQL Server,Transact-SQL...

# 2

another example?

execute('
select
identity(int,1,1) as id,
sum(trunk.count) as count,
sum(trunk.duration) as duration,
sum(trunk.charge1) as charge1,
trunk.trunk,
trunk.currency
into
#utilisation
from
(
select
count(local.callid) as count,
sum(local.duration) as duration,
sum(isnull(local.charge1,''0'')) as charge1,
local.trunk,
local.currency
from
tt32.dbo.trunk t,
database.dbo.local01 local
where
local.trunk = t.trunk
group by

local.trunk,
local.currency
)trunk
group by

trunk.trunk,
trunk.currency

--showing the result
select
id,
isnull(count,''0'') as count,
duration,
isnull(charge1,''0'') as charge1,
trunk,
currency
from #utilisation

keisuke at 2007-10-3 >

# 3

: (

Ok. Thanks!

Bye!

DenisBittencourtMuniz at 2007-10-3 >

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