Thanks for the reply ... Project > Properties > Compile > Build Output Path was set to bin\Release\ ... you say it should also be set to bin\Debug ... not sure how to add a second path name ... can I put a semicolon aftger the first and then enter the second? The MSBuild project buil output verbosity" was set to minimal ... I changed it to Detailed. I built the project and saw the following in the Output window (sorry for the formatting):
Target CopyFilesToOutputDirectory:
Task "Copy"
Copying file from "obj\Release\SWYwindows.exe" to "bin\Release\SWYwindows.exe".
Command:
copy /y "obj\Release\SWYwindows.exe" "bin\Release\SWYwindows.exe"
Done executing task "Copy".
Task "Message"
SWYwindows -> C:\Documents and Settings\SWY.STEVE\My Documents\SWY Stuff\VB and VB .Net\My VB 2005 Projects\SWYwindows\bin\Release\SWYwindows.exe
Done executing task "Message".
Task "Copy"
Done executing task "Copy".
Task "Copy" skipped, due to false condition; ('$(_SGenDllCreated)'=='true') was evaluated as ('false'=='true').
Task "Copy"
Copying file from "obj\Release\SWYwindows.pdb" to "bin\Release\SWYwindows.pdb".
Command:
copy /y "obj\Release\SWYwindows.pdb" "bin\Release\SWYwindows.pdb"
Done executing task "Copy".
Task "Copy"
Copying file from "obj\Release\SWYwindows.xml" to "bin\Release\SWYwindows.xml".
Command:
copy /y "obj\Release\SWYwindows.xml" "bin\Release\SWYwindows.xml"
Done executing task "Copy".
Task "Copy"
Done executing task "Copy".
Task "Copy"
Done executing task "Copy".