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Different color on overloaded operators

I think there should be a setting where you could set another color for overloaded operators. Because if you have'nt seen the overloaded operator the code can create some errors in the code.

I'm seventeen and come from Denmark, so my english can be ugly

Best regards
Lasse Espeholt

[362 byte] By [espeholt_jr] at [2007-12-24]

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# 1

Lasse,

Thanks for the suggestion! I've added it to the list of suggestions that we prioritize for each version. This falls under a category of suggestions that we've seen that have to do with somehow visually conveying more information about a type/method/operator etc. For example, another suggestion is to colorize types which implement IDisposable (differently from normal types). Yet another is to colorize properties differently than field accesses. Colorization is an option, but it's starting to become overloaded. We currently use colorization to denote different token kinds (operators vs. keywords vs. literals vs. strings vs. etc.), "bound" types (types that can be resolved), and disabled code. We'll probably look at different options moving forward.

A great place to enter suggestions is on http://connect.microsoft.com/VisualStudio/Feedback. The beauty of that site is that it's possible for you to track the suggestion and to see when (and if) it will be added to VS.

Anson

AnsonHortonMSFT at 2007-10-8 >

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